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0.25x^2-0.25x-1.5=0
a = 0.25; b = -0.25; c = -1.5;
Δ = b2-4ac
Δ = -0.252-4·0.25·(-1.5)
Δ = 1.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{1.5625}}{2*0.25}=\frac{0.25-\sqrt{1.5625}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{1.5625}}{2*0.25}=\frac{0.25+\sqrt{1.5625}}{0.5} $
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